Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t result=0;
    uint8_t bit=0;
    for(int i=0; i<8; i++){
        bit |= (val >> (7-i))&0x1;
        result |= bit << i;
        bit=0;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach