Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t val1;
    int i=0, j=7;
    while(i<j){
        int lsb=(val>>i)&1;
        int msb=(val>>j)&1;
        if(msb!=lsb){
            val^=(1<<i);
            val^=(1<<j);
        }
        i++;
        j--;
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach