Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t newVal = 0;

    for (int i = 0; i < 8; i++) {
        uint8_t bit = (val >> i) & 1;
        newVal |= bit << (7 - i);
    }

    return newVal;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach