Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t bit=0;
    uint8_t reg;
    int i=8;
    while(i){
     bit <<= 1;             
        reg = val & 1;        
        bit |= reg;             
        val >>= 1;    
    i--;
    }
    
    return bit;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach