Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val)
{
    uint8_t Rev_val = 0;
    for(uint8_t ui8Index=0;ui8Index <=7;ui8Index++)
    {
      Rev_val = Rev_val << 1;
      Rev_val = (( val & 0x01) | Rev_val );
      val = val >> 1;
    }
    return Rev_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach