Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    const size_t size_of_input = sizeof(val) * 8; 
    uint8_t res = 0; 
    for (int i = 0; i < size_of_input; i++)
    {
        res |= ((val >> i) & 1) << (size_of_input - 1 - i);
    }

    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach