Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t nv = 0;
    int i = 8;
    while (i--) {
        nv |= (val & 0x1);
        if (i > 0) {
            nv <<= 1;
            val >>= 1;
        }
    }
    return nv;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach