Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    int i = 0;
    uint8_t ret = 0;
    while (i < 8) {
        uint8_t bit = (val >> i) & 0x1;
        ret |= (bit << (7 - i));
        i++;
    }
    return ret;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach