Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    return 
        ((val & 0x80) >> 7) |
        ((val & 0x40) >> 5) |
        ((val & 0x20) >> 3) |
        ((val & 0x10) >> 1) |
        ((val & 0x08) << 1) |
        ((val & 0x04) << 3) |
        ((val & 0x02) << 5) |
        ((val & 0x01) << 7);
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88