Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t result;
    for(size_t i = 0; i < 8; ++i) {
        result |= ( ( val & 1 ) << ( 8 - ( i + 1 ) ) );
        val = ( val >> 1 ) | ( val << 7 );
        val &= 0xFF;
        result &= 0xFF;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach