Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t res;

    //do not use while as 0's may end the loop
    for(int i=0;i<8;i++)
    {
        res <<=1; // ledt shift res by 1 bit
        res |= (val & 1); //Extract LSB of val and store in result
        val >>=1; //right shift val by 1
    }
    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}