Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    int i = 0;
    uint8_t result = 0;
    while(i<8)
    {
        result = (result << 1) | ((val >> i) & 0x1);
        i++;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach