Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t cnt=0;
    uint8_t tmp=0;
    uint8_t rs=0;
    while (cnt<8){
         tmp=val&1;
         val>>=1;
         rs|=(tmp<<(7-cnt));
         cnt++;
         
    }
    return rs;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach