Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t num;
    num= val << 7 | (val << 5) & 0x40 | (val << 3) & 0x20 | (val << 1) & 0x10;
    num |= (val >> 1) & 0x08 | (val >> 3) & 0x04 | (val >> 5) & 0x02 | val >> 7;
    return num;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88