Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
     uint8_t reversed = 0x0;
    uint8_t cur = 0x0;

    for (int i = 7; i >= 0; i--) {
        cur = (val >> i) & 0x01;
        reversed |= ((cur & 0x01) << (7 - i));
    }
    
    return reversed;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88