Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t result =0;
    int i=0;
    int bit;
    while((val >=0) && (i<8)){
        bit = val%2;
        val/=2;
        result |= (bit << (7-i));
        i++; 
    }
    return result; 
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach