Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    
    uint8_t ans =0;
    for(int i=0; i<8; i++){
        if(val&(1<<i)){
            ans = (ans<<1)|1;
        } else {
            ans = ans<<1;
        }
    }

    return ans;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}