Bit Reversal in an 8-bit Value

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    int result = 0;
    for(int i =0;i<8;i++)
    {
        result<<=1;
        result |= (val & 1);
        val >>= 1;
        // val = (val>>i) | (val<< (8-i));
        // printf("\n%d", val);
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}