Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
uint8_t reg =0,temp=0;
int count = 0;
for(int i=7 ; i>=0 ;i--,count++) {
    temp =(( val >> i) &  1 );
    reg |= temp << count;
    temp = 0; 
}
   return reg;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    //printf("%b", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88