Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val=(((val<<4)&0xF0) |(val>>4)&0x0F);
    val=((val <<2)&0xCC) |((val >>2)&0x33);
    val=((val<<1)&0xAA)|((val>>1)&0x55);
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach