Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here

    uint8_t result = 0;
    uint8_t m = (1U);

    for(int i = 0; i< 8; i++){
        result = result << 1;

        if(m & val){
            result |= 0b1;
            
        }
        m = m << 1;
    }

    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach