Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    if (val == 0 || val == 255) {return val;}

    uint8_t res = 0;

    for (int i = 0 ; i < 8 ; i++) {
        res |= (((val >> 7 - i) & 1) << i);
    }

    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88