Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t reversed_val = 0;
    for (uint8_t index = 0; index < 8; index++) {
        reversed_val = reversed_val << 1;
        reversed_val |= ((val >> index) & 1);
    }
    return reversed_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach