Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    volatile uint8_t i;
    uint8_t res = 0;
    for(i=0;i<8;i++){
        res <<= 1;

        res |= val & 0x01;

        val >>= 1;
    }
    return res;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

Initialize result = 0

Loop 8 times:

shift res left by 1

copy the last bit of val to result

shift the val to the right

return res