Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    for(int i=0;i<4;i++){
        if(((val>>i)&1)!=((val>>(7-i)&1))){
            val^=(1<<i);
            val^=(1<<(7-i));
            //printf("%d ",i);
        }
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach