Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) 
{
    int l,r;
    for(int i=7,j=0;i>j;i--,j++)
    {
        l=(val>>i)&1;
        r=(val>>j)&1;
        if(l!=r)
        {
            val ^=1<<i;
            val ^=1<<j;
        }
    }
    // Your logic here
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach