Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic her
    uint8_t result=0;
    int n=0;
    for (int i=7;i>=0;i--){
        result|= ((val&1)<<i);
        val>>=1;
        n+=1;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach