Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
     uint32_t rev = 0;

    for (int i = 0; i < 8; i++)
    {
        rev <<= 1;          
        rev |= (val & 1);   
        val>>= 1;           
    }

    return rev;
    }
    
// }

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach