Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t reversed = 0;

    for(int i=0;i<8;i++){
        uint8_t bit = (val >> i)&1;
        reversed = (reversed | (bit << (7-i)));
    }
    return reversed;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach