Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
     uint8_t result = 0;

    for (int i = 0; i < 8; i++) {
        // Shift result left to make room for next bit
        result <<= 1;

        // Take LSB from input and add to result
        result |= (val & 1);

        // Shift input right to process next bit
        val >>= 1;
    }
    return result;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach