Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t rev = 0;

    for (int i = 0; i < 8; i++) {
        rev <<= 1;          // Shift reversed bits left
        rev |= (val & 1);   // Add LSB of val to rev
        val >>= 1;          // Shift val right for next bit
    }

    return rev;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach