Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val = ((val&0x55)<<1) | ((val&0xAA)>>1);
    val = ((val&0x33)<<2) | ((val&0xCC)>>2);
    val = ((val&0x0F)<<4) | ((val&0xF0)>>4);

    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach