Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) 
{ 
    uint8_t res=0;
    for(int i=0;i<8;i++)
    {
     res <<=1;
     res |= (val & 1U);
     val >>=1;
     
    }
    return res;
}
int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

26

Expected Output

88