Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
      uint8_t rev;
      for(uint8_t i=0;i<8;i++)
      {
        rev<<=1;
        rev|=(val&1);
       val>>=1;

      }
    return rev;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach