Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    val = val>>4 |val<<4;   // swap nibble
    val= (val&0xCC)>>2 |(val&0x33)<<2;
    val= (val&0xAA)>>1 | (val&0x55)<<1;
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88