Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    for(int i=0;i<4;i++)
    {
        
        uint8_t temp1=(val>>i)&1;
        uint8_t temp2=(val>>(7-i))&1;
        if(temp1&1)
        val|=(1<<(7-i));
        else
        val&=~(1<<(7-i));
        if(temp2&1)
        val|=(1<<i);
        else
        val&=~(1<<i);
    }
    return val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88