Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    // Your logic here
    uint8_t new_val = 0;

    for(int i=0;i<8;i++){
        new_val = new_val << 1;
        if((val >> i)&1){
            new_val = (new_val | 1);
        }
    }
    return new_val;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach