Bit Reversal in an 8-bit Value

Code

#include <stdio.h>
#include <stdint.h>

uint8_t reverse_bits(uint8_t val) {
    uint8_t count = 0;
    uint8_t lret = 0x0;

    while(count < 8)
    {
        lret |= (((val >> count) & 0x1) << (7 - count));
        count++;
    }
    return lret;
}

int main() {
    uint8_t val;
    scanf("%hhu", &val);

    uint8_t result = reverse_bits(val);
    printf("%u", result);
    return 0;
}

Solving Approach

 

 

 

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Input

26

Expected Output

88