Calculate Array Sum Using Only Pointers

Code

#include <stdio.h>

int calculate_sum(int *ptr, int n) {
    // Your logic here
    int sum = 0;
    for(int i=0;i<n;i++)
    {
        sum += *ptr;
        ptr++;
    }
    return sum;
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int result = calculate_sum(arr, n);
    printf("%d", result);

    return 0;
}

Solving Approach

• Start
  1. Declare an integer n
  2. Read n from user input
  3. Declare an integer array arr[100]
  4. For i from 0 to n-1, do:
     • Read arr[i] from user input
  5. Call function calculate_sum(arr, n):
     • Initialize sum ← 0
     • Set pointer ptr ← arr
     • For i from 0 to n-1, do:
       • Add value pointed by ptr to sum
       • Increment ptr to point to next element
     • Return sum
  6. Store returned value in result
  7. Print result
  8. End