52. Calculate Array Sum Using Only Pointers

#include <stdio.h>

int calculate_sum(int *ptr, int n) {
    // Your logic here
    int sum = 0;
    for(int i = 0; i < n/2; i++)
    {
        //sum += *(ptr + i);
        sum += *(ptr + (n - 1 -i)) + *(ptr + i);
    }
    if(n%2 != 0)
    {
        sum += *(ptr + n/2);
    }
    return sum;
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) 
    {
        scanf("%d", &arr[i]);
    }

    int result = calculate_sum(arr, n);
    printf("%d", result);

    return 0;
}