#include <stdio.h>
int isKthBitSet(int n, int k) {
// Use AND to check the bit index in reg correspond to 1 after shift k bit index
//If the result after AND equal to the check bit (1 after shift) mean that all the
//bit in reg after AND will equal to 0 except the bit AND with the check bit, it
//equal to check bit mean that bit in that position in reg is 1 , otherwise if
//result is 0 mean that bit in that position in reg is 0 so that it AND with check
//bit will become 0 too (all other bit become 0 surely)
int check_bit = (1 << k);
int temp;
temp = n & check_bit;
if(temp == check_bit){
return 1;
}
else{
return 0;
}
}
int main() {
int n, k;
scanf("%d %d", &n, &k);
printf("%d", isKthBitSet(n, k));
return 0;
}
Input
8 3
Expected Output
1