Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int alphaCount=0,digitCount=0,others=0;
    for(int i=0;str[i]!='\0';i++){
        if(str[i]>='0'&&str[i]<='9')digitCount++;
        else if(str[i]>='A'&&str[i]<='Z'||(str[i]>='a'&&str[i]<='z'))alphaCount++;
    else others++;

    }
   if((digitCount!=0&&alphaCount!=0)||others!=0)printf("%s","MIXED");
   else if(digitCount==0&&alphaCount!=0)printf("%s","ALPHABETIC");
   else printf("%s","NUMERIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC