Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    bool alph = false,numeric = false,mixed = false;
    int i = 0;
    while(str[i] != '\0'){
        if(((str[i] >= 'A')&&(str[i] <= 'Z'))||((str[i]>='a')&&(str[i]<='z'))){
            alph = true;
        }else if((str[i]>='0')&&(str[i]<='9')){
            numeric = true;
        }else{
            mixed = true;
        }
        i++;
    }
    if((mixed)||(alph&&numeric)){
        printf("MIXED");
    }else if(alph){
        printf("ALPHABETIC");
    }else if(numeric){
        printf("NUMERIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach