Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t numeric = 0, alpha = 0, mixed = 0;

    while (*str != '\0') {
        if ((*str >= 'a' && *str <= 'z') || (*str >= 'A' && *str <= 'Z')) {
            alpha = 1;
        } else if (*str >= '0' && *str <= '9') {
            numeric = 1;
        } else {
            mixed = 1;
        }

        if (mixed || (numeric && alpha)) {
            printf("MIXED");
            return;
        }
        str++;
    }

    // Assuming the given string is not empty
    printf((numeric) ? "NUMERIC" : "ALPHABETIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach