Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int num_l = 0;
    int alp_l = 0;

    for(int i=0; str[i] !='\0'; i++)
    {
        if((str[i] >= '0') && (str[i] <= '9'))
        {
            num_l = 1;
        }
        else if(((str[i] >= 'a') && (str[i] <= 'z'))
        ||((str[i] >= 'A') && (str[i] <= 'Z')))
        {
            alp_l = 1;
        }
        else{
            alp_l = 1;
            num_l = 1;
            break;
        }
    }

    if((num_l == 1) && (alp_l == 0))
    {
        printf("NUMERIC");
    }
    if((num_l == 0) && (alp_l == 1))
    {
        printf("ALPHABETIC");
    }

    if((num_l == 1) && (alp_l == 1))
    {
        printf("MIXED");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC