Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int num_count=0;
    int alpha_count=0;
    int others=0;
    for(int i=0;str[i]!='\0';i++){
        if(str[i]>='0' && str[i]<='9')
            num_count++;
        else if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))
            alpha_count++;
        else
            others++;
    }
    if(num_count>0 && alpha_count==0 && others==0)
        printf("NUMERIC");
    else if(num_count==0 && alpha_count>0 && others==0)
        printf("ALPHABETIC");
    else
        printf("MIXED");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach