99. Check if the String Numeric or Alphabetic

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
#include <stdint.h>

bool isAlpha(char cur) {
    return ((cur >= 'a' && cur <= 'z') || (cur >= 'A' && cur <= 'Z'));
}

bool isNum(char cur) {
    return (cur >= '0' && cur <= '9');
}

void classify_string(const char *str) {
    // Your logic here
    bool hasAlpha = false;
    bool hasNum = false;
    bool mixed = false;

    for(int i = 0; str[i] != '\0'; ++i) {
        if (isAlpha(str[i])) {
            hasAlpha = true;
        }
        else if (isNum(str[i])) {
            hasNum = true;
        }
        else {mixed = true;}
        
    }
    if (hasAlpha && hasNum) {mixed = true;}

    if (mixed) {
        printf("MIXED");
    }
    else if (hasAlpha) {
        printf("ALPHABETIC");
    }
    else {
        printf("NUMERIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote