Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t isAlpha = 0;
    uint8_t isDigit = 0;
    uint8_t i = 0;

    if (str[0] == '\0')
    {
        printf("MIXED");
        return;
    }

    while (str[i] != '\0')
    {
        if (str[i] >= '0' && str[i] <= '9')
        {
            isDigit = 1;
        }else if (str[i] >= 'A' && str[i] <= 'Z' || str[i] >= 'a' && str[i] <= 'z')
        {
            isAlpha = 1;
        }else {
            printf("MIXED");
            return;
        }
        if (isAlpha && isDigit) {
            printf("MIXED");
            return;
        }
        i++;
    }
    if (isAlpha){
        printf("ALPHABETIC");
    }else if (isDigit)
    {
        printf("NUMERIC");
    }else {
        printf("MIXED");
    }

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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Input

123456

Expected Output

NUMERIC