Check if the String Numeric or Alphabetic

Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    uint8_t i = 0;
    uint8_t is_numeric = 0, is_alphabetic = 0, is_mixed = 0;
    while(str[i]!='\0')
    {
        if(str[i]>='0' && str[i] <= '9')
            is_numeric = 1;
        else if((str[i]>='a' && str[i] <= 'z') || (str[i]>='A' && str[i] <= 'Z'))
            is_alphabetic = 1;
        else
            is_mixed = 1;
        i++;
    }
    if((is_alphabetic==1 && is_numeric==1) || is_mixed==1)
        printf("MIXED");
    else if(is_alphabetic==1)
        printf("ALPHABETIC");
    else if(is_numeric==1)
        printf("NUMERIC");
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach