99. Check if the String Numeric or Alphabetic

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Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    bool num=false;
        bool apl=false;
            for(int i=0;str[i]!='\0';i++){
                    if(str[i]>='0'&&str[i]<='9'){
                                num=true;
                                        }else if ((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z')){
                                                    apl=true;
                                                            }else{
                                                                printf("MIXED");
                                                                return;
                                                            }
                                                                    
                                                                        
                                                                            }
                                                                                if(num==true&&apl==false){
                                                                                        printf("NUMERIC");
                                                                                            }else if(num==false&&apl==true){
                                                                                                    printf("ALPHABETIC");
                                                                                                        }else{
                                                                                                                printf("MIXED");
                                                                                                                    }
                                                                                                                    }

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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