99. Check if the String Numeric or Alphabetic

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Code

#include <stdio.h>
#include <stdint.h>

void classify_string(const char *str) {
    // Your logic here
    int count_NUMERIC=0;
    int count_ALPHABETIC=0;
    int count_MIXED =0;
    for(int i =0; str[i] != '\0';i++){
        if(*(str + i) >= 'a' && *(str + i) <= 'z' ||*(str + i) >= 'A' && *(str + i) <= 'Z'){
            count_ALPHABETIC++;
        }else if(*(str + i) >= '0' && *(str + i) <= '9'){
            count_NUMERIC++;
        }else{
            count_MIXED++;
        }
    }
    if(count_ALPHABETIC !=0 && count_NUMERIC !=0 || count_MIXED !=0){
        printf("MIXED");
    }else if(count_ALPHABETIC ==0 && count_NUMERIC !=0){
        printf("NUMERIC");
    }else if(count_ALPHABETIC !=0 && count_NUMERIC ==0){
        printf("ALPHABETIC");
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    classify_string(str);
    return 0;
}

Solving Approach

 

 

 

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